5. Two-Way Slab Deflection Control (Serviceability Requirements)

Since the slab thickness was selected based on the minimum slab thickness tables in ACI 318-14, the deflection calculations are not required. However, the calculations of immediate and time-dependent deflections are covered in this section for illustration and comparison with spSlab model results.

5.1. Immediate (Instantaneous) Deflections

The calculation of deflections for two-way slabs is challenging even if linear elastic behavior can be assumed. Elastic analysis for three service load levels (D, D + Lsustained, D+LFull) is used to obtain immediate deflections of the two-way slab in this example. However, other procedures may be used if they result in predictions of deflection in reasonable agreement with the results of comprehensive tests.

ACI 318-14 (24.2.3)

The effective moment of inertia (Ie) is used to account for the cracking effect on the flexural stiffness of the slab. Ie for uncracked section (Mcr > Ma) is equal to Ig. When the section is cracked (Mcr < Ma), then the following equation should be used:

ACI 318-14 (Eq. 24.2.3.5a)

Where:

Ma

=

Maximum moment in member due to service loads at stage deflection is calculated.

The values of the maximum moments for the three service load levels are calculated from structural analysis as shown previously in this document. These moments are shown in the following Figure.

13 Moment service load

Figure 13 – Maximum Moments for the Three Service Load Levels

Mcr

=

cracking moment.

ACI 318-14 (Eq. 24.2.3.5b)

fr

=

Modulus of rapture of concrete.

Ig

=

Moment of inertia of the gross uncracked concrete section

Icr

=

moment of inertia of the cracked section transformed to concrete.

The calculations shown below are for the design strip (frame strip). The values of these parameters for column and middle strips are shown in Table 9.

As calculated previously, the exterior span frame strip near the interior support is reinforced with 17 #4 bars located at 1.25 in. along the section from the top of the slab. Figure 14 shows all the parameters needed to calculate the moment of inertia of the cracked section transformed to concrete.

14 Cracked transformed section

Figure 14 – Cracked Transformed Section

Ecs = Modulus of elasticity of slab concrete.

ACI 318-14 (19.2.2.1.a)

PCA Notes on ACI 318-11 (Table 10-2)

PCA Notes on ACI 318-11 (Table 10-2)

PCA Notes on ACI 318-11 (Table 10-2)

PCA Notes on ACI 318-11 (Table 10-2)

The effective moment of inertia procedure described in the Code is considered sufficiently accurate to estimate deflections. The effective moment of inertia, Ie, was developed to provide a transition between the upper and lower bounds of Ig and Icr as a function of the ratio Mcr/Ma. For conventionally reinforced (nonprestressed) members, the effective moment of inertia, Ie, shall be calculated by Eq. (24.2.3.5a) unless obtained by a more comprehensive analysis.

Ie shall be permitted to be taken as the value obtained from Eq. (24.2.3.5a) at midspan for simple and continuous spans, and at the support for cantilevers.

ACI 318-14 (24.2.3.7)

For continuous one-way slabs and beams. Ie shall be permitted to be taken as the average of values obtained from Eq. (24.2.3.5a) for the critical positive and negative moment sections.

ACI 318-14 (24.2.3.6)

For the exterior span (span with one end continuous) with service load level (D + LLfull):

Since Mcr = 54.23 ft-kips < Ma = 64.13 ft-kips

ACI 318-14 (24.2.3.5a)

Where Ie- is the effective moment of inertia for the critical negative moment section (near the support).

Where Ie+ is the effective moment of inertia for the critical positive moment section (midspan).

Since midspan stiffness (including the effect of cracking) has a dominant effect on deflections, midspan section is heavily represented in calculation of Ie and this is considered satisfactory in approximate deflection calculations. The averaged effective moment of inertia (Ie,avg) is given by:

PCA Notes on ACI 318-11 (9.5.2.4(1))

Where:

Ie-

=

The effective moment of inertia for the critical negative moment section near the support.

Ie+

=

The effective moment of inertia for the critical positive moment section (midspan).

For the interior span (span with both ends continuous) with service load level (D + LLfull):

ACI 318-14 (24.2.3.5a)

The averaged effective moment of inertia (Ie,avg) is given by:

PCA Notes on ACI 318-11 (9.5.2.4(2))

Where:

Ie,L-

=

The effective moment of inertia for the critical negative moment section near the left support.

Ie,R-

=

The effective moment of inertia for the critical negative moment section near the right support.

The following Table provides a summary of the required parameters and calculated values needed for deflections for exterior and interior equivalent frame. It also provides a summary of the same values for column strip and middle strip to facilitate calculation of panel deflection.

Table 9 – Averaged Effective Moment of Inertia Calculations

For Frame Strip

Span

zone

Ig 
(in.4)

Icr
(in.4)

Ma, (ft-kip)

Mcr
(k-ft)

Ie (in.4)

Ie,avg (in.4)

D

D +
LLSus

D +
Lfull

D

D +
LLSus

D +
Lfull

D

D +
LLSus

D +
Lfull

Ext

Left

4802

499

-25.99

-25.99

-35.65

54.23

4802

4802

4802

4802

4802

4555

Midspan

466

25.03

25.03

34.35

4802

4802

4802

Right

629

-46.74

-46.74

-64.13

4802

4802

3153

Int

Left

629

-42.45

-42.45

-58.24

4802

4802

3999

4802

4802

4561

Mid

466

18.51

18.51

25.39

4802

4802

4802

Right

629

-42.45

-42.45

-58.24

4802

4802

3999

Deflections in two-way slab systems shall be calculated taking into account size and shape of the panel, conditions of support, and nature of restraints at the panel edges. For immediate deflections two-way slab systems the midpanel deflection is computed as the sum of deflection at midspan of the column strip or column line in one direction (Δcx or Δcy) and deflection at midspan of the middle strip in the orthogonal direction (Δmx or Δmy). Figure 15 shows the deflection computation for a rectangular panel. The average Δ for panels that have different properties in the two direction is calculated as follows:

 

PCA Notes on ACI 318-11 (9.5.3.4 Eq. 8)

15 Deflections

Figure 15 – Deflection Computation for a Rectangular Panel

To calculate each term of the previous equation, the following procedure should be used. Figure 16 shows the procedure of calculating the term Δcx. same procedure can be used to find the other terms.

16 Deflections calculations procedure

Figure 16 – Δcx Calculation Procedure

For exterior span - service dead load case:

PCA Notes on ACI 318-11 (9.5.3.4 Eq. 10)

Where:

Δframe_fixed = Deflection of column strip assuming fixed-end condition.

ACI 318-14 (19.2.2.1.a)

Iframe,averaged = The averaged effective moment of inertia (Ie,avg) for the frame strip for service dead load case from Table 9 = 4,802 in.4

PCA Notes on ACI 318-11 (9.5.3.4 Eq. 11)

Where LDFc is the load distribution factor for the column strip. The load distribution factor for the column strip can be found from the following equation:

And the load distribution factor for the middle strip can be found from the following equation:

For the end span, LDF for exterior negative region (LDFL¯), interior negative region (LDFR¯), and positive region (LDFL) are 1.00, 0.75, and 0.60, respectively (From Table 6 of this document). Thus, the load distribution factor for the column strip for the end span is given by:

Ic,g = The gross moment of inertia (Ig) for the column strip for service dead load = 2,401 in.4

PCA Notes on ACI 318-11 (9.5.3.4 Eq. 12)

Where:

θc,L

=

Rotation of the left support

(Mnet,L)frame

=

25.99 ft-kips = Net frame strip negative moment of the left support

Kec 

=

Effective column stiffness = 554.07 × 106 in.-lb (calculated previously).

PCA Notes on ACI 318-11 (9.5.3.4 Eq. 14)

Where:

Δθc,L

=

Midspan deflection due to rotation of left support.

(Ig / Ie)frame

=

Gross to effective moment of inertia ratio for frame strip.

Where:

θc,R

=

Rotation of the span right support.

(Mnet,R)frame

=

Net frame strip negative moment of the right support.

Where:

Δθc,R

=

Midspan deflection due to rotation of right support.

PCA Notes on ACI 318-11 (9.5.3.4 Eq. 9)

Following the same procedure, Δmx can be calculated for the middle strip. This procedure is repeated for the equivalent frame in the orthogonal direction to obtain Δcy, and Δmy for the end and middle spans for the other load levels (D+LLsus and D+LLfull).

Assuming square panel, Δcx = Δcy= 0.0747 in. and Δmx = Δmy= 0.0386 in.

The average Δ for the corner panel is calculated as follows:

Table 10 – Immediate (Instantaneous) Deflections in the x-direction

Column Strip

Middle Strip

Span

LDF

D

LDF

D

Δframe-fixed

(in.)

Δc-fixed

(in.)

θc1

(rad)

θc2

(rad)

Δθc1

(in.)

Δθc2

(in.)

Δcx

(in.)

Δframe-fixed

(in.)

Δm-fixed

(in.)

θm1

(rad)

θm2

(rad)

Δθm1

(in.)

Δθm2

(in.)

Δmx

(in.)

Ext

0.738

0.0386

0.0570

0.0006

0.0001

0.0152

0.0025

0.0747

0.263

0.0386

0.0203

0.0006

0.0001

0.0152

0.0025

0.0380

Int

0.675

0.0386

0.0521

-0.0001

-0.0001

-0.0025

-0.0025

0.0471

0.325

0.0386

0.0251

-0.0001

-0.0001

-0.0025

-0.0025

0.0201

Span

LDF

D+LLsus

LDF

D+LLsus

Δframe-fixed

(in.)

Δc-fixed

(in.)

θc1

(rad)

θc2

(rad)

Δθc1

(in.)

Δθc2

(in.)

Δcx

(in.)

Δframe-fixed

(in.)

Δm-fixed

(in.)

θm1

(rad)

θm2

(rad)

Δθm1

(in.)

Δθm2

(in.)

Δmx

(in.)

Ext

0.738

0.0386

0.0570

0.0006

0.0001

0.0152

0.0025

0.0747

0.263

0.0386

0.0203

0.0006

0.0001

0.0152

0.0025

0.0380

Int

0.675

0.0386

0.0521

-0.0001

-0.0001

-0.0025

-0.0025

0.0471

0.325

0.0386

0.0251

-0.0001

-0.0001

-0.0025

-0.0025

0.0201

Span

LDF

D+LLfull

LDF

D+LLfull

Δframe-fixed

(in.)

Δc-fixed

(in.)

θc1

(rad)

θc2

(rad)

Δθc1

(in.)

Δθc2

(in.)

Δcx

(in.)

Δframe-fixed

(in.)

Δm-fixed

(in.)

θm1

(rad)

θm2

(rad)

Δθm1

(in.)

Δθm2

(in.)

Δmx

(in.)

Ext

0.738

0.0559

0.0782

0.0008

0.0001

0.0208

0.0052

0.1042

0.263

0.0559

0.0278

0.0008

0.0001

0.0208

0.0052

0.0539

Int

0.675

0.0558

0.0715

-0.0001

-0.0001

-0.0041

-0.0041

0.0633

0.325

0.0558

0.0344

-0.0001

-0.0001

-0.0041

-0.0041

0.0262

Span

LDF

LL

LDF

LL

Δcx

(in.)

Δmx

(in.)

Ext

0.738

0.0296

0.262

0.0159

Int

0.675

0.0161

0.325

0.0061

From the analysis in the transverse direction the deflection values below are obtained:

For DL loading case:

For DL+LLsust loading case:

For DL+LLfull loading case:

These values for the x-direction are shown in the previous Table. Then, the total midpanel deflection is calculated by combining the contributions of the column and middle strip deflections from the X and Y directions:

 

PCA Notes on ACI 318-11 (9.5.3.4 Eq. 8)

5.2. Time-Dependent (Long-Term) Deflections (Δlt)

The additional time-dependent (long-term) deflection resulting from creep and shrinkage (Δcs) may be estimated as follows:

PCA Notes on ACI 318-11 (9.5.2.5 Eq. 4)

The total time-dependent (long-term) deflection is calculated as:

CSA A23.3-04 (N9.8.2.5)

Where:

sust)Inst

=

Immediate (instantaneous) deflection due to sustained load, in.

ACI 318-14 (24.2.4.1.1)

total)lt

=

Time-dependent (long-term) total deflection, in.

total)Inst

=

Total immediate (instantaneous) deflection, in.

For the exterior span

ξ = 2, consider the sustained load duration to be 60 months or more.

ACI 318-14 (Table 24.2.4.1.3)

ρ` = 0, conservatively.

 

The following Table shows long-term deflections for the exterior and interior spans for the analysis in the x-direction, for column and middle strips.

Table 11 - Long-Term Deflections

Column Strip

Span

sust)Inst (in.)

λΔ

Δcs (in.)

total)Inst (in.)

total)lt (in.)

Exterior

0.0747

2

0.149

0.104

0.254

Interior

0.0471

2

0.094

0.063

0.157

Middle Strip

Exterior

0.0380

2

0.076

0.054

0.130

Interior

0.0201

2

0.040

0.026

0.066